Online Aptitude Test

(0.04)-1.5 =		4		-1.5
		100

=		1		-(3/2)
		25

   = (25)^(3/2)

   = (5²)^(3/2)

   = (5)^{2 x (3/2)}

   = 5³

   = 125.

The square of a natural number never ends in 7.

42437 is not the square of a natural number.

Unit digit in (4137)⁷⁵⁴ = Unit digit in {[(4137)⁴]¹⁸⁸ x (4137)²}

=Unit digit in { 292915317923361 x 17114769 }

= (1 x 9) = 9

Let the side of the square(ABCD) be x metres.

Then, AB + BC = 2x metres.

AC = 2x = (1.41x) m.

Saving on 2x metres = (0.59x) m.

Saving % =		0.59x	x 100	%	= 30% (approx.)
		2x

Let the ten's digit be x.

Then, unit's digit = x + 2.

Number = 10x + (x + 2) = 11x + 2.

Sum of digits = x + (x + 2) = 2x + 2.

 (11x + 2)(2x + 2) = 144

 22x² + 26x - 140 = 0

 11x² + 13x - 70 = 0

 (x - 2)(11x + 35) = 0

 x = 2.

Hence, required number = 11x + 2 = 24.

Let A = 2k, B = 3k and C = 5k.

A's new salary =	115	of 2k =		115	x 2k		=	23k
	100			100				10

B's new salary =	110	of 3k =		110	x 3k		=	33k
	100			100				10

C's new salary =	120	of 5k =		120	x 5k		= 6k
	100			100

New ratio		23k	:	33k	: 6k		= 23 : 33 : 60
		10		10

Cost Price (C.P.) = Rs. (4700 + 800) = Rs. 5500.

Selling Price (S.P.) = Rs. 5800.

Gain = (S.P.) - (C.P.) = Rs.(5800 - 5500) = Rs. 300.

Gain % =		300	x 100	%	= 5	5	%
		5500				11

Let original length = x and original breadth = y.

Original area = xy.

New breadth = 3y.

New area =		x	x 3y		=	3	xy.
		2				2

Increase % =		1	xy x	1	x 100	%	= 50%.
		2		xy

The century divisible by 400 is a leap year.

 The year 700 is not a leap year.

Since the number is greater than the number obtained on reversing the digits, so the ten's digit is greater than the unit's digit.

Let ten's and unit's digits be 2x and x respectively.

Then, (10 x 2x + x) - (10x + 2x) = 36

 9x = 36

 x = 4.

 Required difference = (2x + x) - (2x - x) = 2x = 8.

Required number of ways = (⁷C₅ x ³C₂) = (⁷C₂ x ³C₁) =7 x 6x 3= 63.2 x 1

15^th August, 2010 = (2009 years + Period 1.1.2010 to 15.8.2010)

Odd days in 1600 years = 0

Odd days in 400 years = 0

9 years = (2 leap years + 7 ordinary years) = (2 x 2 + 7 x 1) = 11 odd days  4 odd days.

Jan.  Feb.   March    April    May  June  July  Aug. 
(31 +  28  +  31   +   30   +  31  + 30  + 31  + 15) = 227 days

 227 days = (32 weeks + 3 days)  3 odd days.

Total number of odd days = (0 + 0 + 4 + 3) = 7  0 odd days.

Given day is Sunday.

Let the ages of Kunal and Sagar 6 years ago be 6x and 5x years respectively.

 10(6x + 10) = 11(5x + 10)

 5x = 10

 x = 2.

 Sagar's present age = (5x + 6) = 16 years.

Given Exp. = 8988 x1/8x1/4=2247/8= 280.875

Simran : Nanda = (50000 x 36) : (80000 x 30) = 3 : 4.

Simran's share = Rs.		24500 x	3		= Rs. 10,500.
			7

90 = 10 x 9

Clearly, 653xy is divisible by 10, so y = 0

Now, 653x0 is divisible by 9.

So, (6 + 5 + 3 + x + 0) = (14 + x) is divisible by 9. So, x = 4.

Hence, (x + y) = (4 + 0) = 4.

C.P. of 6 toffees = Re. 1

For Re. 1, toffees sold =		6 x	5		= 5.
			6